X^2-3.2x+2.4=0

Solution for X^2-3.2x+2.4=0 equation:

X^2-3.2X+2.4=0

a = 1; b = -3.2; c = +2.4;
Δ = b2-4ac
Δ = -3.22-4·1·2.4
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.2)-\sqrt{0.64}}{2*1}=\frac{3.2-\sqrt{0.64}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.2)+\sqrt{0.64}}{2*1}=\frac{3.2+\sqrt{0.64}}{2}
$